Base | Representation |
---|---|
bin | 10001011100011010… |
… | …11011100000001101 |
3 | 220011200021210220111 |
4 | 20232031123200031 |
5 | 123134443111203 |
6 | 4145144520021 |
7 | 451035642436 |
oct | 105615334015 |
9 | 26150253814 |
10 | 9365207053 |
11 | 3a76462744 |
12 | 1994480011 |
13 | b6332c147 |
14 | 64bb2048d |
15 | 39c2bb26d |
hex | 22e35b80d |
9365207053 has 2 divisors, whose sum is σ = 9365207054. Its totient is φ = 9365207052.
The previous prime is 9365207029. The next prime is 9365207069. The reversal of 9365207053 is 3507025639.
9365207053 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6346034244 + 3019172809 = 79662^2 + 54947^2 .
It is a cyclic number.
It is not a de Polignac number, because 9365207053 - 25 = 9365207021 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 9365206997 and 9365207015.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (9365207083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4682603526 + 4682603527.
It is an arithmetic number, because the mean of its divisors is an integer number (4682603527).
Almost surely, 29365207053 is an apocalyptic number.
It is an amenable number.
9365207053 is a deficient number, since it is larger than the sum of its proper divisors (1).
9365207053 is an equidigital number, since it uses as much as digits as its factorization.
9365207053 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 170100, while the sum is 40.
The square root of 9365207053 is about 96773.9998811664. Note that the first 3 decimals coincide. The cubic root of 9365207053 is about 2107.8472126738.
The spelling of 9365207053 in words is "nine billion, three hundred sixty-five million, two hundred seven thousand, fifty-three".
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