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93832428373 is a prime number
BaseRepresentation
bin101011101100011011…
…0010011101101010101
322222012100021020111221
41113120312103231111
53014132100201443
6111034522330341
76531153324055
oct1273066235525
9288170236457
1093832428373
1136880a61272
12162283599b1
138b04b01a88
144781cb1565
152692a50eed
hex15d8d93b55

93832428373 has 2 divisors, whose sum is σ = 93832428374. Its totient is φ = 93832428372.

The previous prime is 93832428311. The next prime is 93832428427. The reversal of 93832428373 is 37382423839.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 68297027569 + 25535400804 = 261337^2 + 159798^2 .

It is a cyclic number.

It is not a de Polignac number, because 93832428373 - 213 = 93832420181 is a prime.

It is a super-2 number, since 2×938324283732 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 93832428373.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (93832428073) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 46916214186 + 46916214187.

It is an arithmetic number, because the mean of its divisors is an integer number (46916214187).

Almost surely, 293832428373 is an apocalyptic number.

It is an amenable number.

93832428373 is a deficient number, since it is larger than the sum of its proper divisors (1).

93832428373 is an equidigital number, since it uses as much as digits as its factorization.

93832428373 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5225472, while the sum is 52.

The spelling of 93832428373 in words is "ninety-three billion, eight hundred thirty-two million, four hundred twenty-eight thousand, three hundred seventy-three".