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93931304393 is a prime number
BaseRepresentation
bin101011101111010111…
…1011111010111001001
322222110020022122220202
41113132233133113021
53014332403220033
6111052413501545
76533463625253
oct1273657372711
9288406278822
1093931304393
1136921855293
12162554a18b5
138b1c440ab4
14479108ccd3
15269b5828e8
hex15debdf5c9

93931304393 has 2 divisors, whose sum is σ = 93931304394. Its totient is φ = 93931304392.

The previous prime is 93931304351. The next prime is 93931304407. The reversal of 93931304393 is 39340313939.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 78017986489 + 15913317904 = 279317^2 + 126148^2 .

It is an emirp because it is prime and its reverse (39340313939) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 93931304393 - 26 = 93931304329 is a prime.

It is not a weakly prime, because it can be changed into another prime (93931304303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 46965652196 + 46965652197.

It is an arithmetic number, because the mean of its divisors is an integer number (46965652197).

Almost surely, 293931304393 is an apocalyptic number.

It is an amenable number.

93931304393 is a deficient number, since it is larger than the sum of its proper divisors (1).

93931304393 is an equidigital number, since it uses as much as digits as its factorization.

93931304393 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 708588, while the sum is 47.

The spelling of 93931304393 in words is "ninety-three billion, nine hundred thirty-one million, three hundred four thousand, three hundred ninety-three".