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941121020121151 is a prime number
BaseRepresentation
bin1101010111111100011101000…
…0000110000101000000111111
311120102020021212000220100000011
43111333013100012011000333
51441323311322122334101
613133333010020444051
7402142515132661462
oct32577072006050077
94512207760810004
10941121020121151
1125296320197a681
1289677685549627
13315194400c286c
14128587011d72d9
1573c0ab67bd751
hex357f1d018503f

941121020121151 has 2 divisors, whose sum is σ = 941121020121152. Its totient is φ = 941121020121150.

The previous prime is 941121020121131. The next prime is 941121020121179. The reversal of 941121020121151 is 151121020121149.

941121020121151 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-941121020121151 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (941121020121131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 470560510060575 + 470560510060576.

It is an arithmetic number, because the mean of its divisors is an integer number (470560510060576).

Almost surely, 2941121020121151 is an apocalyptic number.

941121020121151 is a deficient number, since it is larger than the sum of its proper divisors (1).

941121020121151 is an equidigital number, since it uses as much as digits as its factorization.

941121020121151 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 31.

The spelling of 941121020121151 in words is "nine hundred forty-one trillion, one hundred twenty-one billion, twenty million, one hundred twenty-one thousand, one hundred fifty-one".