Base | Representation |
---|---|
bin | 10001100010001011… |
… | …00100111010110001 |
3 | 220022001010100002121 |
4 | 20301011210322301 |
5 | 123234322330423 |
6 | 4154031314241 |
7 | 452163155302 |
oct | 106105447261 |
9 | 26261110077 |
10 | 9413480113 |
11 | 3aa0733a34 |
12 | 19a867b981 |
13 | b7033149b |
14 | 6542c87a9 |
15 | 3a165445d |
hex | 231164eb1 |
9413480113 has 2 divisors, whose sum is σ = 9413480114. Its totient is φ = 9413480112.
The previous prime is 9413480093. The next prime is 9413480173. The reversal of 9413480113 is 3110843149.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7790357169 + 1623122944 = 88263^2 + 40288^2 .
It is a cyclic number.
It is not a de Polignac number, because 9413480113 - 217 = 9413349041 is a prime.
It is a super-3 number, since 3×94134801133 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (9413480173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4706740056 + 4706740057.
It is an arithmetic number, because the mean of its divisors is an integer number (4706740057).
Almost surely, 29413480113 is an apocalyptic number.
It is an amenable number.
9413480113 is a deficient number, since it is larger than the sum of its proper divisors (1).
9413480113 is an equidigital number, since it uses as much as digits as its factorization.
9413480113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10368, while the sum is 34.
The square root of 9413480113 is about 97023.0906176463. The cubic root of 9413480113 is about 2111.4626481773.
The spelling of 9413480113 in words is "nine billion, four hundred thirteen million, four hundred eighty thousand, one hundred thirteen".
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