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942113000311253 is a prime number
BaseRepresentation
bin1101011000110110001100011…
…0101110001100100111010101
311120112202010022211122012111222
43112031203012232030213111
51441441034411034430003
613135412423142540125
7402304263256322531
oct32615430656144725
94515663284565458
10942113000311253
11253205974927701
12897b7989737645
133158bb4aa00554
141289072649abc1
1573db7c3e24c38
hex358d8c6b8c9d5

942113000311253 has 2 divisors, whose sum is σ = 942113000311254. Its totient is φ = 942113000311252.

The previous prime is 942113000311247. The next prime is 942113000311261. The reversal of 942113000311253 is 352113000311249.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 504624197400964 + 437488802910289 = 22463842^2 + 20916233^2 .

It is a cyclic number.

It is not a de Polignac number, because 942113000311253 - 216 = 942113000245717 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (942113000311753) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 471056500155626 + 471056500155627.

It is an arithmetic number, because the mean of its divisors is an integer number (471056500155627).

Almost surely, 2942113000311253 is an apocalyptic number.

It is an amenable number.

942113000311253 is a deficient number, since it is larger than the sum of its proper divisors (1).

942113000311253 is an equidigital number, since it uses as much as digits as its factorization.

942113000311253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19440, while the sum is 35.

The spelling of 942113000311253 in words is "nine hundred forty-two trillion, one hundred thirteen billion, three hundred eleven thousand, two hundred fifty-three".