Base | Representation |
---|---|
bin | 10101011100101100110010… |
… | …001101011110100111010111 |
3 | 110100222222100011011101000012 |
4 | 111130230302031132213113 |
5 | 44331010304013203434 |
6 | 532343054220310435 |
7 | 25604130204516233 |
oct | 2534546215364727 |
9 | 410888304141005 |
10 | 94331209116119 |
11 | 28069706377978 |
12 | a6b602b0a241b |
13 | 4083519643781 |
14 | 1941924dd35c3 |
15 | ad8b87d5b3ce |
hex | 55cb3235e9d7 |
94331209116119 has 2 divisors, whose sum is σ = 94331209116120. Its totient is φ = 94331209116118.
The previous prime is 94331209116103. The next prime is 94331209116167. The reversal of 94331209116119 is 91161190213349.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 94331209116119 - 24 = 94331209116103 is a prime.
It is a super-2 number, since 2×943312091161192 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (94331209136119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47165604558059 + 47165604558060.
It is an arithmetic number, because the mean of its divisors is an integer number (47165604558060).
Almost surely, 294331209116119 is an apocalyptic number.
94331209116119 is a deficient number, since it is larger than the sum of its proper divisors (1).
94331209116119 is an equidigital number, since it uses as much as digits as its factorization.
94331209116119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 314928, while the sum is 50.
The spelling of 94331209116119 in words is "ninety-four trillion, three hundred thirty-one billion, two hundred nine million, one hundred sixteen thousand, one hundred nineteen".
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