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94331211213061 is a prime number
BaseRepresentation
bin10101011100101100110010…
…010101011110100100000101
3110100222222100022002220110201
4111130230302111132210011
544331010310032304221
6532343054333250501
725604130231401614
oct2534546225364405
9410888308086421
1094331211213061
112806970757a389
12a6b602b933a31
134083519bc9074
1419419253bb87b
15ad8b88122891
hex55cb3255e905

94331211213061 has 2 divisors, whose sum is σ = 94331211213062. Its totient is φ = 94331211213060.

The previous prime is 94331211212971. The next prime is 94331211213077. The reversal of 94331211213061 is 16031211213349.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76512090800161 + 17819120412900 = 8747119^2 + 4221270^2 .

It is a cyclic number.

It is not a de Polignac number, because 94331211213061 - 227 = 94331076995333 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 94331211213061.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (94331211219061) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47165605606530 + 47165605606531.

It is an arithmetic number, because the mean of its divisors is an integer number (47165605606531).

Almost surely, 294331211213061 is an apocalyptic number.

It is an amenable number.

94331211213061 is a deficient number, since it is larger than the sum of its proper divisors (1).

94331211213061 is an equidigital number, since it uses as much as digits as its factorization.

94331211213061 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23328, while the sum is 37.

The spelling of 94331211213061 in words is "ninety-four trillion, three hundred thirty-one billion, two hundred eleven million, two hundred thirteen thousand, sixty-one".