Base | Representation |
---|---|
bin | 10101011100101100110010… |
… | …010101011110100100010011 |
3 | 110100222222100022002220111020 |
4 | 111130230302111132210103 |
5 | 44331010310032304300 |
6 | 532343054333250523 |
7 | 25604130231401634 |
oct | 2534546225364423 |
9 | 410888308086436 |
10 | 94331211213075 |
11 | 2806970757a3a1 |
12 | a6b602b933a43 |
13 | 4083519bc9085 |
14 | 19419253bb88b |
15 | ad8b881228a0 |
hex | 55cb3255e913 |
94331211213075 has 96 divisors (see below), whose sum is σ = 160564127738112. Its totient is φ = 48847389504000.
The previous prime is 94331211213061. The next prime is 94331211213077. The reversal of 94331211213075 is 57031211213349.
It is not a de Polignac number, because 94331211213075 - 213 = 94331211204883 is a prime.
It is a super-2 number, since 2×943312112130752 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (94331211213077) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 448350052 + ... + 448560398.
It is an arithmetic number, because the mean of its divisors is an integer number (1672542997272).
Almost surely, 294331211213075 is an apocalyptic number.
94331211213075 is a deficient number, since it is larger than the sum of its proper divisors (66232916525037).
94331211213075 is a wasteful number, since it uses less digits than its factorization.
94331211213075 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 211685 (or 211680 counting only the distinct ones).
The product of its (nonzero) digits is 136080, while the sum is 42.
The spelling of 94331211213075 in words is "ninety-four trillion, three hundred thirty-one billion, two hundred eleven million, two hundred thirteen thousand, seventy-five".
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