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9483041053 is a prime number
BaseRepresentation
bin10001101010011101…
…11011100100011101
3220110220000101202201
420311032323210131
5123410124303203
64204554251501
7453666343003
oct106516734435
926426011681
109483041053
114026a25112
121a07a26b91
13b818781c5
1465d634a73
153a77e4e1d
hex2353bb91d

9483041053 has 2 divisors, whose sum is σ = 9483041054. Its totient is φ = 9483041052.

The previous prime is 9483041041. The next prime is 9483041111. The reversal of 9483041053 is 3501403849.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6606113284 + 2876927769 = 81278^2 + 53637^2 .

It is an emirp because it is prime and its reverse (3501403849) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 9483041053 - 225 = 9449486621 is a prime.

It is a super-2 number, since 2×94830410532 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (9483041023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4741520526 + 4741520527.

It is an arithmetic number, because the mean of its divisors is an integer number (4741520527).

Almost surely, 29483041053 is an apocalyptic number.

It is an amenable number.

9483041053 is a deficient number, since it is larger than the sum of its proper divisors (1).

9483041053 is an equidigital number, since it uses as much as digits as its factorization.

9483041053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 37.

The square root of 9483041053 is about 97380.9070249400. The cubic root of 9483041053 is about 2116.6507764144.

The spelling of 9483041053 in words is "nine billion, four hundred eighty-three million, forty-one thousand, fifty-three".