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948329384117 is a prime number
BaseRepresentation
bin11011100110011001101…
…01100000100010110101
310100122210201001011200212
431303030311200202311
5111014134310242432
62003353445515205
7125341325523023
oct15631465404265
93318721034625
10948329384117
1133620323a465
12133961712b05
136b57239a10b
1433c83cbd713
1519a053c42b2
hexdcccd608b5

948329384117 has 2 divisors, whose sum is σ = 948329384118. Its totient is φ = 948329384116.

The previous prime is 948329384087. The next prime is 948329384161. The reversal of 948329384117 is 711483923849.

948329384117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 925455544036 + 22873840081 = 962006^2 + 151241^2 .

It is an emirp because it is prime and its reverse (711483923849) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 948329384117 - 26 = 948329384053 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (948329386117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 474164692058 + 474164692059.

It is an arithmetic number, because the mean of its divisors is an integer number (474164692059).

Almost surely, 2948329384117 is an apocalyptic number.

It is an amenable number.

948329384117 is a deficient number, since it is larger than the sum of its proper divisors (1).

948329384117 is an equidigital number, since it uses as much as digits as its factorization.

948329384117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 10450944, while the sum is 59.

The spelling of 948329384117 in words is "nine hundred forty-eight billion, three hundred twenty-nine million, three hundred eighty-four thousand, one hundred seventeen".