Base | Representation |
---|---|
bin | 101100001110101110… |
… | …0110001101010110101 |
3 | 100002011112221210100201 |
4 | 1120131130301222311 |
5 | 3024011220111003 |
6 | 111345035040501 |
7 | 6601530160252 |
oct | 1303534615265 |
9 | 302145853321 |
10 | 94983363253 |
11 | 373116a5719 |
12 | 164a98a0131 |
13 | 8c593a752c |
14 | 4850aac429 |
15 | 270dae8b1d |
hex | 161d731ab5 |
94983363253 has 2 divisors, whose sum is σ = 94983363254. Its totient is φ = 94983363252.
The previous prime is 94983363173. The next prime is 94983363257. The reversal of 94983363253 is 35236338949.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 60151486564 + 34831876689 = 245258^2 + 186633^2 .
It is a cyclic number.
It is not a de Polignac number, because 94983363253 - 229 = 94446492341 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 94983363194 and 94983363203.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (94983363257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47491681626 + 47491681627.
It is an arithmetic number, because the mean of its divisors is an integer number (47491681627).
Almost surely, 294983363253 is an apocalyptic number.
It is an amenable number.
94983363253 is a deficient number, since it is larger than the sum of its proper divisors (1).
94983363253 is an equidigital number, since it uses as much as digits as its factorization.
94983363253 is an evil number, because the sum of its binary digits is even.
The product of its digits is 12597120, while the sum is 55.
The spelling of 94983363253 in words is "ninety-four billion, nine hundred eighty-three million, three hundred sixty-three thousand, two hundred fifty-three".
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