Search a number
-
+
95000120011001 is a prime number
BaseRepresentation
bin10101100110011011110000…
…011010000010100011111001
3110110100220220201000121000102
4111212123300122002203321
544422440221210323001
6534014241434245145
726003350351355312
oct2546336032024371
9413326821017012
1095000120011001
11282a7363109767
12a7a37abb867b5
13410161bbb090a
14196605d389609
15aeb2878a6e6b
hex5666f06828f9

95000120011001 has 2 divisors, whose sum is σ = 95000120011002. Its totient is φ = 95000120011000.

The previous prime is 95000120010997. The next prime is 95000120011003. The reversal of 95000120011001 is 10011002100059.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 75218760765625 + 19781359245376 = 8672875^2 + 4447624^2 .

It is a cyclic number.

It is not a de Polignac number, because 95000120011001 - 22 = 95000120010997 is a prime.

It is a super-2 number, since 2×950001200110012 (a number of 29 digits) contains 22 as substring.

Together with 95000120011003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (95000120011003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47500060005500 + 47500060005501.

It is an arithmetic number, because the mean of its divisors is an integer number (47500060005501).

Almost surely, 295000120011001 is an apocalyptic number.

It is an amenable number.

95000120011001 is a deficient number, since it is larger than the sum of its proper divisors (1).

95000120011001 is an equidigital number, since it uses as much as digits as its factorization.

95000120011001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90, while the sum is 20.

The spelling of 95000120011001 in words is "ninety-five trillion, one hundred twenty million, eleven thousand, one".