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95114963 is a prime number
BaseRepresentation
bin1011010101101…
…01011011010011
320121222100012102
411222311123103
5143322134323
613234351015
72233315046
oct552653323
9217870172
1095114963
1149765309
1227a2b46b
1316923158
14c8bcc5d
15853c328
hex5ab56d3

95114963 has 2 divisors, whose sum is σ = 95114964. Its totient is φ = 95114962.

The previous prime is 95114951. The next prime is 95114989. The reversal of 95114963 is 36941159.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 95114963 - 24 = 95114947 is a prime.

It is a super-3 number, since 3×951149633 (a number of 25 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (95114993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47557481 + 47557482.

It is an arithmetic number, because the mean of its divisors is an integer number (47557482).

Almost surely, 295114963 is an apocalyptic number.

95114963 is a deficient number, since it is larger than the sum of its proper divisors (1).

95114963 is an equidigital number, since it uses as much as digits as its factorization.

95114963 is an evil number, because the sum of its binary digits is even.

The product of its digits is 29160, while the sum is 38.

The square root of 95114963 is about 9752.6900391636. The cubic root of 95114963 is about 456.4742472297.

The spelling of 95114963 in words is "ninety-five million, one hundred fourteen thousand, nine hundred sixty-three".