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95254703 is a prime number
BaseRepresentation
bin1011010110101…
…11100010101111
320122020102212222
411223113202233
5143341122303
613241345555
72234436335
oct553274257
9218212788
1095254703
11498502a5
1227a982bb
131697193b
14c917b55
158568938
hex5ad78af

95254703 has 2 divisors, whose sum is σ = 95254704. Its totient is φ = 95254702.

The previous prime is 95254669. The next prime is 95254711. The reversal of 95254703 is 30745259.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 95254703 - 26 = 95254639 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (95254403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47627351 + 47627352.

It is an arithmetic number, because the mean of its divisors is an integer number (47627352).

Almost surely, 295254703 is an apocalyptic number.

95254703 is a deficient number, since it is larger than the sum of its proper divisors (1).

95254703 is an equidigital number, since it uses as much as digits as its factorization.

95254703 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 37800, while the sum is 35.

The square root of 95254703 is about 9759.8515869864. The cubic root of 95254703 is about 456.6976838529.

It can be divided in two parts, 952 and 54703, that added together give a palindrome (55655).

The spelling of 95254703 in words is "ninety-five million, two hundred fifty-four thousand, seven hundred three".