Base | Representation |
---|---|
bin | 11011101111011000000… |
… | …00000001011101111111 |
3 | 10101010020110121122120021 |
4 | 31313230000001131333 |
5 | 111104021140421112 |
6 | 2005511512233011 |
7 | 125601606351412 |
oct | 15675400013577 |
9 | 3333213548507 |
10 | 953147201407 |
11 | 338255823945 |
12 | 13488709b767 |
13 | 6bb5c56c48b |
14 | 341bdab9b79 |
15 | 19bd8340907 |
hex | ddec00177f |
953147201407 has 2 divisors, whose sum is σ = 953147201408. Its totient is φ = 953147201406.
The previous prime is 953147201353. The next prime is 953147201417. The reversal of 953147201407 is 704102741359.
It is a strong prime.
It is an emirp because it is prime and its reverse (704102741359) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-953147201407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (953147201417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 476573600703 + 476573600704.
It is an arithmetic number, because the mean of its divisors is an integer number (476573600704).
Almost surely, 2953147201407 is an apocalyptic number.
953147201407 is a deficient number, since it is larger than the sum of its proper divisors (1).
953147201407 is an equidigital number, since it uses as much as digits as its factorization.
953147201407 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 211680, while the sum is 43.
The spelling of 953147201407 in words is "nine hundred fifty-three billion, one hundred forty-seven million, two hundred one thousand, four hundred seven".
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