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953252595597053 is a prime number
BaseRepresentation
bin1101100010111110100110101…
…0010101110111111011111101
311122000012001120101110011001202
43120233221222111313323331
51444421042303433101203
613215222110305545245
7404534140651050533
oct33057515225677375
94560161511404052
10953252595597053
11256810178a74a04
128aab68a5645225
1331bb9445bb431b
1412b579595d0153
15753144aa0a388
hex362fa6a577efd

953252595597053 has 2 divisors, whose sum is σ = 953252595597054. Its totient is φ = 953252595597052.

The previous prime is 953252595597037. The next prime is 953252595597061. The reversal of 953252595597053 is 350795595252359.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 923870797029049 + 29381798568004 = 30395243^2 + 5420498^2 .

It is a cyclic number.

It is not a de Polignac number, because 953252595597053 - 24 = 953252595597037 is a prime.

It is a super-2 number, since 2×9532525955970532 (a number of 31 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (953252595597083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 476626297798526 + 476626297798527.

It is an arithmetic number, because the mean of its divisors is an integer number (476626297798527).

Almost surely, 2953252595597053 is an apocalyptic number.

It is an amenable number.

953252595597053 is a deficient number, since it is larger than the sum of its proper divisors (1).

953252595597053 is an equidigital number, since it uses as much as digits as its factorization.

953252595597053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2870437500, while the sum is 74.

The spelling of 953252595597053 in words is "nine hundred fifty-three trillion, two hundred fifty-two billion, five hundred ninety-five million, five hundred ninety-seven thousand, fifty-three".