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953271311413 is a prime number
BaseRepresentation
bin11011101111100110110…
…01011101110000110101
310101010120010011002111011
431313303121131300311
5111104244423431123
62005532104312221
7125604644311231
oct15676331356065
93333503132434
10953271311413
113383098925a3
12134900772671
136bb7c1a5055
14341d23855c1
1519be41a8e0d
hexddf365dc35

953271311413 has 2 divisors, whose sum is σ = 953271311414. Its totient is φ = 953271311412.

The previous prime is 953271311359. The next prime is 953271311437. The reversal of 953271311413 is 314113172359.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 788440995364 + 164830316049 = 887942^2 + 405993^2 .

It is a cyclic number.

It is not a de Polignac number, because 953271311413 - 217 = 953271180341 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (953271317413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 476635655706 + 476635655707.

It is an arithmetic number, because the mean of its divisors is an integer number (476635655707).

Almost surely, 2953271311413 is an apocalyptic number.

It is an amenable number.

953271311413 is a deficient number, since it is larger than the sum of its proper divisors (1).

953271311413 is an equidigital number, since it uses as much as digits as its factorization.

953271311413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 68040, while the sum is 40.

The spelling of 953271311413 in words is "nine hundred fifty-three billion, two hundred seventy-one million, three hundred eleven thousand, four hundred thirteen".