Base | Representation |
---|---|
bin | 1000101010111110001100… |
… | …1000001010111111001001 |
3 | 1020202110210202102200222011 |
4 | 2022233203020022333021 |
5 | 2222202313302000014 |
6 | 32140003335255521 |
7 | 2002555623221242 |
oct | 212574310127711 |
9 | 36673722380864 |
10 | 9534343000009 |
11 | 3046546077863 |
12 | 109b9a021a5a1 |
13 | 542114099239 |
14 | 24d671071cc9 |
15 | 1180243637c4 |
hex | 8abe320afc9 |
9534343000009 has 2 divisors, whose sum is σ = 9534343000010. Its totient is φ = 9534343000008.
The previous prime is 9534343000001. The next prime is 9534343000067. The reversal of 9534343000009 is 9000003434359.
9534343000009 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8999982000009 + 534361000000 = 2999997^2 + 731000^2 .
It is a cyclic number.
It is not a de Polignac number, because 9534343000009 - 23 = 9534343000001 is a prime.
It is not a weakly prime, because it can be changed into another prime (9534343000001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4767171500004 + 4767171500005.
It is an arithmetic number, because the mean of its divisors is an integer number (4767171500005).
Almost surely, 29534343000009 is an apocalyptic number.
It is an amenable number.
9534343000009 is a deficient number, since it is larger than the sum of its proper divisors (1).
9534343000009 is an equidigital number, since it uses as much as digits as its factorization.
9534343000009 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 174960, while the sum is 40.
The spelling of 9534343000009 in words is "nine trillion, five hundred thirty-four billion, three hundred forty-three million, nine", and thus it is an aban number.
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