Base | Representation |
---|---|
bin | 1000101010111110001100… |
… | …1000001010111111000001 |
3 | 1020202110210202102200221212 |
4 | 2022233203020022333001 |
5 | 2222202313302000001 |
6 | 32140003335255505 |
7 | 2002555623221231 |
oct | 212574310127701 |
9 | 36673722380855 |
10 | 9534343000001 |
11 | 3046546077856 |
12 | 109b9a021a595 |
13 | 542114099231 |
14 | 24d671071cc1 |
15 | 1180243637bb |
hex | 8abe320afc1 |
9534343000001 has 2 divisors, whose sum is σ = 9534343000002. Its totient is φ = 9534343000000.
The previous prime is 9534342999911. The next prime is 9534343000009. The reversal of 9534343000001 is 1000003434359.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9282137155600 + 252205844401 = 3046660^2 + 502201^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-9534343000001 is a prime.
It is not a weakly prime, because it can be changed into another prime (9534343000009) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4767171500000 + 4767171500001.
It is an arithmetic number, because the mean of its divisors is an integer number (4767171500001).
Almost surely, 29534343000001 is an apocalyptic number.
It is an amenable number.
9534343000001 is a deficient number, since it is larger than the sum of its proper divisors (1).
9534343000001 is an equidigital number, since it uses as much as digits as its factorization.
9534343000001 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19440, while the sum is 32.
The spelling of 9534343000001 in words is "nine trillion, five hundred thirty-four billion, three hundred forty-three million, one", and thus it is an aban number.
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