9539713453 has 2 divisors, whose sum is σ = 9539713454. Its totient is φ = 9539713452.

The previous prime is 9539713411. The next prime is 9539713471. The reversal of 9539713453 is 3543179359.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5138452489 + 4401260964 = 71683^2 + 66342^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-9539713453 is a prime.

It is a super-2 number, since 2×9539713453² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 9539713397 and 9539713406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (9539713153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4769856726 + 4769856727.

It is an arithmetic number, because the mean of its divisors is an integer number (4769856727).

Almost surely, 2^9539713453 is an apocalyptic number.

It is an amenable number.

9539713453 is a deficient number, since it is larger than the sum of its proper divisors (1).

9539713453 is an equidigital number, since it uses as much as digits as its factorization.

9539713453 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1530900, while the sum is 49.

The square root of 9539713453 is about 97671.4566953928. The cubic root of 9539713453 is about 2120.8589029684.

The spelling of 9539713453 in words is "nine billion, five hundred thirty-nine million, seven hundred thirteen thousand, four hundred fifty-three".