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95499905191253 is a prime number
BaseRepresentation
bin10101101101101101001101…
…111011001100110101010101
3110112010200221121000022221222
4111231231031323030311111
5100004132301212110003
6535040014545220125
726054432451325223
oct2555551573146525
9415120847008858
1095499905191253
112847a311891982
12a864631031645
1341397aa685ac4
141982311c4db13
15b09289704c38
hex56db4deccd55

95499905191253 has 2 divisors, whose sum is σ = 95499905191254. Its totient is φ = 95499905191252.

The previous prime is 95499905191121. The next prime is 95499905191289. The reversal of 95499905191253 is 35219150999459.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95025512098609 + 474393092644 = 9748103^2 + 688762^2 .

It is a cyclic number.

It is not a de Polignac number, because 95499905191253 - 224 = 95499888414037 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (95499905151253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47749952595626 + 47749952595627.

It is an arithmetic number, because the mean of its divisors is an integer number (47749952595627).

Almost surely, 295499905191253 is an apocalyptic number.

It is an amenable number.

95499905191253 is a deficient number, since it is larger than the sum of its proper divisors (1).

95499905191253 is an equidigital number, since it uses as much as digits as its factorization.

95499905191253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 177147000, while the sum is 71.

The spelling of 95499905191253 in words is "ninety-five trillion, four hundred ninety-nine billion, nine hundred five million, one hundred ninety-one thousand, two hundred fifty-three".