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9550831755401 is a prime number
BaseRepresentation
bin1000101011111011100111…
…1011110010000010001001
31020211001100212221021010022
42022332321323302002021
52222440100412133101
632151331434430225
72004011341303346
oct212767173620211
936731325837108
109550831755401
113052537599832
1210a3022292375
1354384119b331
14250396cad7cd
1511868bc00a1b
hex8afb9ef2089

9550831755401 has 2 divisors, whose sum is σ = 9550831755402. Its totient is φ = 9550831755400.

The previous prime is 9550831755349. The next prime is 9550831755503. The reversal of 9550831755401 is 1045571380559.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 4807060635001 + 4743771120400 = 2192501^2 + 2178020^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-9550831755401 is a prime.

It is a super-2 number, since 2×95508317554012 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (9550831751401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4775415877700 + 4775415877701.

It is an arithmetic number, because the mean of its divisors is an integer number (4775415877701).

Almost surely, 29550831755401 is an apocalyptic number.

It is an amenable number.

9550831755401 is a deficient number, since it is larger than the sum of its proper divisors (1).

9550831755401 is an equidigital number, since it uses as much as digits as its factorization.

9550831755401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3780000, while the sum is 53.

The spelling of 9550831755401 in words is "nine trillion, five hundred fifty billion, eight hundred thirty-one million, seven hundred fifty-five thousand, four hundred one".