Base | Representation |
---|---|
bin | 1011011010001… |
… | …00011110011101 |
3 | 20200002002221112 |
4 | 11231010132131 |
5 | 143444412033 |
6 | 13255111405 |
7 | 2241305231 |
oct | 555043635 |
9 | 220062845 |
10 | 95700893 |
11 | 4a025552 |
12 | 28072565 |
13 | 16a99a62 |
14 | c9d25c1 |
15 | 8605c48 |
hex | 5b4479d |
95700893 has 2 divisors, whose sum is σ = 95700894. Its totient is φ = 95700892.
The previous prime is 95700863. The next prime is 95700901. The reversal of 95700893 is 39800759.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 92871769 + 2829124 = 9637^2 + 1682^2 .
It is an emirp because it is prime and its reverse (39800759) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 95700893 - 28 = 95700637 is a prime.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 95700893.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (95700823) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47850446 + 47850447.
It is an arithmetic number, because the mean of its divisors is an integer number (47850447).
Almost surely, 295700893 is an apocalyptic number.
It is an amenable number.
95700893 is a deficient number, since it is larger than the sum of its proper divisors (1).
95700893 is an equidigital number, since it uses as much as digits as its factorization.
95700893 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 68040, while the sum is 41.
The square root of 95700893 is about 9782.6833230970. The cubic root of 95700893 is about 457.4096577762.
The spelling of 95700893 in words is "ninety-five million, seven hundred thousand, eight hundred ninety-three".
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