Base | Representation |
---|---|
bin | 101100101000010010… |
… | …0110101011100011111 |
3 | 100011101022222001000201 |
4 | 1121100210311130133 |
5 | 3032240311121022 |
6 | 112010115404331 |
7 | 6632014012051 |
oct | 1312044653437 |
9 | 304338861021 |
10 | 95841113887 |
11 | 377118a0442 |
12 | 166a8bb36a7 |
13 | 9064cca59c |
14 | 48d298b8d1 |
15 | 275e07c127 |
hex | 165093571f |
95841113887 has 2 divisors, whose sum is σ = 95841113888. Its totient is φ = 95841113886.
The previous prime is 95841113839. The next prime is 95841113891. The reversal of 95841113887 is 78831114859.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 95841113887 - 219 = 95840589599 is a prime.
It is a super-2 number, since 2×958411138872 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (95841113387) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47920556943 + 47920556944.
It is an arithmetic number, because the mean of its divisors is an integer number (47920556944).
Almost surely, 295841113887 is an apocalyptic number.
95841113887 is a deficient number, since it is larger than the sum of its proper divisors (1).
95841113887 is an equidigital number, since it uses as much as digits as its factorization.
95841113887 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1935360, while the sum is 55.
The spelling of 95841113887 in words is "ninety-five billion, eight hundred forty-one million, one hundred thirteen thousand, eight hundred eighty-seven".
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