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95990341 is a prime number
BaseRepresentation
bin1011011100010…
…11001001000101
320200121210222211
411232023021011
5144033142331
613305223421
72243622136
oct556131105
9220553884
1095990341
114a202a67
1228191b71
1316b6b725
14ca69c8d
1586618b1
hex5b8b245

95990341 has 2 divisors, whose sum is σ = 95990342. Its totient is φ = 95990340.

The previous prime is 95990333. The next prime is 95990351. The reversal of 95990341 is 14309959.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 87890625 + 8099716 = 9375^2 + 2846^2 .

It is an emirp because it is prime and its reverse (14309959) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 95990341 - 23 = 95990333 is a prime.

It is a super-3 number, since 3×959903413 (a number of 25 digits) contains 333 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 95990294 and 95990303.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (95990351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 47995170 + 47995171.

It is an arithmetic number, because the mean of its divisors is an integer number (47995171).

Almost surely, 295990341 is an apocalyptic number.

It is an amenable number.

95990341 is a deficient number, since it is larger than the sum of its proper divisors (1).

95990341 is an equidigital number, since it uses as much as digits as its factorization.

95990341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43740, while the sum is 40.

The square root of 95990341 is about 9797.4660499539. The cubic root of 95990341 is about 457.8703398467.

The spelling of 95990341 in words is "ninety-five million, nine hundred ninety thousand, three hundred forty-one".