Base | Representation |
---|---|
bin | 1000101110110010011010… |
… | …1100000110000110110001 |
3 | 1020222202000121101011112002 |
4 | 2023230212230012012301 |
5 | 2224241044124000423 |
6 | 32230044510543345 |
7 | 2010366332065004 |
oct | 213544654060661 |
9 | 36882017334462 |
10 | 9599901000113 |
11 | 3071327933636 |
12 | 10b0637507b55 |
13 | 548361166988 |
14 | 2528cdb5953b |
15 | 119aae9e1228 |
hex | 8bb26b061b1 |
9599901000113 has 2 divisors, whose sum is σ = 9599901000114. Its totient is φ = 9599901000112.
The previous prime is 9599900999981. The next prime is 9599901000121. The reversal of 9599901000113 is 3110001099959.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8326756614544 + 1273144385569 = 2885612^2 + 1128337^2 .
It is a cyclic number.
It is not a de Polignac number, because 9599901000113 - 212 = 9599900996017 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (9599901500113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4799950500056 + 4799950500057.
It is an arithmetic number, because the mean of its divisors is an integer number (4799950500057).
Almost surely, 29599901000113 is an apocalyptic number.
It is an amenable number.
9599901000113 is a deficient number, since it is larger than the sum of its proper divisors (1).
9599901000113 is an equidigital number, since it uses as much as digits as its factorization.
9599901000113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 98415, while the sum is 47.
The spelling of 9599901000113 in words is "nine trillion, five hundred ninety-nine billion, nine hundred one million, one hundred thirteen", and thus it is an aban number.
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