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9599901000113 is a prime number
BaseRepresentation
bin1000101110110010011010…
…1100000110000110110001
31020222202000121101011112002
42023230212230012012301
52224241044124000423
632230044510543345
72010366332065004
oct213544654060661
936882017334462
109599901000113
113071327933636
1210b0637507b55
13548361166988
142528cdb5953b
15119aae9e1228
hex8bb26b061b1

9599901000113 has 2 divisors, whose sum is σ = 9599901000114. Its totient is φ = 9599901000112.

The previous prime is 9599900999981. The next prime is 9599901000121. The reversal of 9599901000113 is 3110001099959.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8326756614544 + 1273144385569 = 2885612^2 + 1128337^2 .

It is a cyclic number.

It is not a de Polignac number, because 9599901000113 - 212 = 9599900996017 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (9599901500113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4799950500056 + 4799950500057.

It is an arithmetic number, because the mean of its divisors is an integer number (4799950500057).

Almost surely, 29599901000113 is an apocalyptic number.

It is an amenable number.

9599901000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

9599901000113 is an equidigital number, since it uses as much as digits as its factorization.

9599901000113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 98415, while the sum is 47.

The spelling of 9599901000113 in words is "nine trillion, five hundred ninety-nine billion, nine hundred one million, one hundred thirteen", and thus it is an aban number.