Base | Representation |
---|---|
bin | 11011111100111100010… |
… | …10000001010101001111 |
3 | 10101211001002121202200122 |
4 | 31332132022001111033 |
5 | 111213430332242111 |
6 | 2013114352215155 |
7 | 126250243640525 |
oct | 15763612012517 |
9 | 3354032552618 |
10 | 960431134031 |
11 | 340353378276 |
12 | 13617a53a4bb |
13 | 6c750638a95 |
14 | 346b1226315 |
15 | 19eb2a42cdb |
hex | df9e28154f |
960431134031 has 2 divisors, whose sum is σ = 960431134032. Its totient is φ = 960431134030.
The previous prime is 960431134027. The next prime is 960431134127. The reversal of 960431134031 is 130431134069.
It is a weak prime.
It is an emirp because it is prime and its reverse (130431134069) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 960431134031 - 22 = 960431134027 is a prime.
It is a super-2 number, since 2×9604311340312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 960431133982 and 960431134000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (960431137031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 480215567015 + 480215567016.
It is an arithmetic number, because the mean of its divisors is an integer number (480215567016).
Almost surely, 2960431134031 is an apocalyptic number.
960431134031 is a deficient number, since it is larger than the sum of its proper divisors (1).
960431134031 is an equidigital number, since it uses as much as digits as its factorization.
960431134031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 23328, while the sum is 35.
The spelling of 960431134031 in words is "nine hundred sixty billion, four hundred thirty-one million, one hundred thirty-four thousand, thirty-one".
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