Base | Representation |
---|---|
bin | 101100101110100001… |
… | …0001011010011100101 |
3 | 100011220220021021020121 |
4 | 1121131002023103211 |
5 | 3033202313212242 |
6 | 112042543401541 |
7 | 6640132436635 |
oct | 1313502132345 |
9 | 304826237217 |
10 | 96050132197 |
11 | 37809882a48 |
12 | 16746bb32b1 |
13 | 90993c1666 |
14 | 491263a6c5 |
15 | 27725b8667 |
hex | 165d08b4e5 |
96050132197 has 2 divisors, whose sum is σ = 96050132198. Its totient is φ = 96050132196.
The previous prime is 96050132183. The next prime is 96050132207. The reversal of 96050132197 is 79123105069.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 93676396356 + 2373735841 = 306066^2 + 48721^2 .
It is a cyclic number.
It is not a de Polignac number, because 96050132197 - 211 = 96050130149 is a prime.
It is a super-2 number, since 2×960501321972 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (96050132137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48025066098 + 48025066099.
It is an arithmetic number, because the mean of its divisors is an integer number (48025066099).
Almost surely, 296050132197 is an apocalyptic number.
It is an amenable number.
96050132197 is a deficient number, since it is larger than the sum of its proper divisors (1).
96050132197 is an equidigital number, since it uses as much as digits as its factorization.
96050132197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 102060, while the sum is 43.
The spelling of 96050132197 in words is "ninety-six billion, fifty million, one hundred thirty-two thousand, one hundred ninety-seven".
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