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96117309802333 is a prime number
BaseRepresentation
bin10101110110101100001110…
…000110111000011101011101
3110121022201120120201020102101
4111312230032012320131131
5100044241222302133313
6540231403232525101
726150150353042501
oct2566541606703535
9417281516636371
1096117309802333
1128698138679376
12a9442186b0791
134182a920a0a41
1419a4161818301
15b1a37251e5dd
hex576b0e1b875d

96117309802333 has 2 divisors, whose sum is σ = 96117309802334. Its totient is φ = 96117309802332.

The previous prime is 96117309802277. The next prime is 96117309802343. The reversal of 96117309802333 is 33320890371169.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 65136085500249 + 30981224302084 = 8070693^2 + 5566078^2 .

It is a cyclic number.

It is not a de Polignac number, because 96117309802333 - 217 = 96117309671261 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (96117309802343) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48058654901166 + 48058654901167.

It is an arithmetic number, because the mean of its divisors is an integer number (48058654901167).

Almost surely, 296117309802333 is an apocalyptic number.

It is an amenable number.

96117309802333 is a deficient number, since it is larger than the sum of its proper divisors (1).

96117309802333 is an equidigital number, since it uses as much as digits as its factorization.

96117309802333 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4408992, while the sum is 55.

The spelling of 96117309802333 in words is "ninety-six trillion, one hundred seventeen billion, three hundred nine million, eight hundred two thousand, three hundred thirty-three".