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9629324893 is a prime number
BaseRepresentation
bin10001111011111001…
…11101011001011101
3220212002021101110201
420331330331121131
5124210101344033
64231301503501
7460423624336
oct107574753135
926762241421
109629324893
1140a1559351
121a48a11b91
13ba5c757a6
14674c3328d
153b558d47d
hex23df3d65d

9629324893 has 2 divisors, whose sum is σ = 9629324894. Its totient is φ = 9629324892.

The previous prime is 9629324863. The next prime is 9629324897. The reversal of 9629324893 is 3984239269.

9629324893 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9396975844 + 232349049 = 96938^2 + 15243^2 .

It is a cyclic number.

It is not a de Polignac number, because 9629324893 - 213 = 9629316701 is a prime.

It is a super-2 number, since 2×96293248932 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (9629324897) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4814662446 + 4814662447.

It is an arithmetic number, because the mean of its divisors is an integer number (4814662447).

Almost surely, 29629324893 is an apocalyptic number.

It is an amenable number.

9629324893 is a deficient number, since it is larger than the sum of its proper divisors (1).

9629324893 is an equidigital number, since it uses as much as digits as its factorization.

9629324893 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5038848, while the sum is 55.

The square root of 9629324893 is about 98129.1235719549. The cubic root of 9629324893 is about 2127.4789906068.

The spelling of 9629324893 in words is "nine billion, six hundred twenty-nine million, three hundred twenty-four thousand, eight hundred ninety-three".