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96415607836817 is a prime number
BaseRepresentation
bin10101111011000010000010…
…000011100101000010010001
3110122101020112111002110101122
4111323002002003211002101
5100114133131101234232
6541020415131012025
726210540433355433
oct2573020203450221
9418336474073348
1096415607836817
11287a26a208a7a5
12a991ba7b9a015
1341a4c50415559
1419b477c8c2653
15b22ed058c312
hex57b0820e5091

96415607836817 has 2 divisors, whose sum is σ = 96415607836818. Its totient is φ = 96415607836816.

The previous prime is 96415607836789. The next prime is 96415607836819. The reversal of 96415607836817 is 71863870651469.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 74128673259601 + 22286934577216 = 8609801^2 + 4720904^2 .

It is a cyclic number.

It is not a de Polignac number, because 96415607836817 - 216 = 96415607771281 is a prime.

It is a super-2 number, since 2×964156078368172 (a number of 29 digits) contains 22 as substring.

Together with 96415607836819, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (96415607836819) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48207803918408 + 48207803918409.

It is an arithmetic number, because the mean of its divisors is an integer number (48207803918409).

Almost surely, 296415607836817 is an apocalyptic number.

It is an amenable number.

96415607836817 is a deficient number, since it is larger than the sum of its proper divisors (1).

96415607836817 is an equidigital number, since it uses as much as digits as its factorization.

96415607836817 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 365783040, while the sum is 71.

The spelling of 96415607836817 in words is "ninety-six trillion, four hundred fifteen billion, six hundred seven million, eight hundred thirty-six thousand, eight hundred seventeen".