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96428043822973 is a prime number
BaseRepresentation
bin10101111011001101100111…
…010011000110011101111101
3110122102102122011121000022111
4111323031213103012131331
5100114334113204313343
6541030233133214021
726211460550454022
oct2573154723063575
9418372564530274
1096428043822973
11287a79a3956205
12a994498931311
1341a61829ab245
1419b51dc391549
15b234ac22dc9d
hex57b3674c677d

96428043822973 has 2 divisors, whose sum is σ = 96428043822974. Its totient is φ = 96428043822972.

The previous prime is 96428043822871. The next prime is 96428043822983. The reversal of 96428043822973 is 37922834082469.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 74774033251204 + 21654010571769 = 8647198^2 + 4653387^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-96428043822973 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 96428043822899 and 96428043822908.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (96428043822983) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48214021911486 + 48214021911487.

It is an arithmetic number, because the mean of its divisors is an integer number (48214021911487).

Almost surely, 296428043822973 is an apocalyptic number.

It is an amenable number.

96428043822973 is a deficient number, since it is larger than the sum of its proper divisors (1).

96428043822973 is an equidigital number, since it uses as much as digits as its factorization.

96428043822973 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 250822656, while the sum is 67.

The spelling of 96428043822973 in words is "ninety-six trillion, four hundred twenty-eight billion, forty-three million, eight hundred twenty-two thousand, nine hundred seventy-three".