Base | Representation |
---|---|
bin | 10110000011101100100010… |
… | …110110011001011100010011 |
3 | 110201111011101011012000100111 |
4 | 112003230202312121130103 |
5 | 100203412022304000313 |
6 | 542154124311102151 |
7 | 26301546200634205 |
oct | 2603544266313423 |
9 | 421434334160314 |
10 | 97011011000083 |
11 | 28a02158701874 |
12 | aa69473371957 |
13 | 42191398c250b |
14 | 19d5502450775 |
15 | b3372ba8e43d |
hex | 583b22d99713 |
97011011000083 has 2 divisors, whose sum is σ = 97011011000084. Its totient is φ = 97011011000082.
The previous prime is 97011010999999. The next prime is 97011011000089. The reversal of 97011011000083 is 38000011011079.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 97011011000083 - 213 = 97011010991891 is a prime.
It is a super-2 number, since 2×970110110000832 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (97011011000089) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48505505500041 + 48505505500042.
It is an arithmetic number, because the mean of its divisors is an integer number (48505505500042).
Almost surely, 297011011000083 is an apocalyptic number.
97011011000083 is a deficient number, since it is larger than the sum of its proper divisors (1).
97011011000083 is an equidigital number, since it uses as much as digits as its factorization.
97011011000083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 31.
The spelling of 97011011000083 in words is "ninety-seven trillion, eleven billion, eleven million, eighty-three", and thus it is an aban number and an uban number.
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