Base | Representation |
---|---|
bin | 10110000011101100100010… |
… | …110110011001011010111111 |
3 | 110201111011101011012000020101 |
4 | 112003230202312121122333 |
5 | 100203412022303444444 |
6 | 542154124311101531 |
7 | 26301546200634025 |
oct | 2603544266313277 |
9 | 421434334160211 |
10 | 97011010999999 |
11 | 28a021587017a8 |
12 | aa694733718a7 |
13 | 42191398c2475 |
14 | 19d5502450715 |
15 | b3372ba8e3d4 |
hex | 583b22d996bf |
97011010999999 has 2 divisors, whose sum is σ = 97011011000000. Its totient is φ = 97011010999998.
The previous prime is 97011010999967. The next prime is 97011011000083. The reversal of 97011010999999 is 99999901011079.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 97011010999999 - 25 = 97011010999967 is a prime.
It is a super-2 number, since 2×970110109999992 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (97011010999949) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48505505499999 + 48505505500000.
It is an arithmetic number, because the mean of its divisors is an integer number (48505505500000).
Almost surely, 297011010999999 is an apocalyptic number.
97011010999999 is a deficient number, since it is larger than the sum of its proper divisors (1).
97011010999999 is an equidigital number, since it uses as much as digits as its factorization.
97011010999999 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 33480783, while the sum is 73.
The spelling of 97011010999999 in words is "ninety-seven trillion, eleven billion, ten million, nine hundred ninety-nine thousand, nine hundred ninety-nine".
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