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97042232184773 is a prime number
BaseRepresentation
bin10110000100001001100111…
…110001110000111111000101
3110201121010222000100112012012
4112010021213301300333011
5100204414442414403043
6542220330325304005
726304032656423241
oct2604114761607705
9421533860315165
1097042232184773
1128a1441a200a47
12aa73527265005
13421c073c884b5
1419d6c24b41421
15b344579daa18
hex584267c70fc5

97042232184773 has 2 divisors, whose sum is σ = 97042232184774. Its totient is φ = 97042232184772.

The previous prime is 97042232184701. The next prime is 97042232184823. The reversal of 97042232184773 is 37748123224079.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95657828152324 + 1384404032449 = 9780482^2 + 1176607^2 .

It is a cyclic number.

It is not a de Polignac number, because 97042232184773 - 232 = 97037937217477 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (97042232184973) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48521116092386 + 48521116092387.

It is an arithmetic number, because the mean of its divisors is an integer number (48521116092387).

Almost surely, 297042232184773 is an apocalyptic number.

It is an amenable number.

97042232184773 is a deficient number, since it is larger than the sum of its proper divisors (1).

97042232184773 is an equidigital number, since it uses as much as digits as its factorization.

97042232184773 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 28449792, while the sum is 59.

The spelling of 97042232184773 in words is "ninety-seven trillion, forty-two billion, two hundred thirty-two million, one hundred eighty-four thousand, seven hundred seventy-three".