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9711219953 is a prime number
BaseRepresentation
bin10010000101101010…
…10111010011110001
3221001210101002101002
421002311113103301
5124342033014303
64243345051345
7462440002421
oct110265272361
927053332332
109711219953
114133804316
121a70326b55
13bb9c1a5c6
14681a70481
153bc868788
hex242d574f1

9711219953 has 2 divisors, whose sum is σ = 9711219954. Its totient is φ = 9711219952.

The previous prime is 9711219913. The next prime is 9711219971. The reversal of 9711219953 is 3599121179.

9711219953 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8872132864 + 839087089 = 94192^2 + 28967^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-9711219953 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 9711219898 and 9711219907.

It is not a weakly prime, because it can be changed into another prime (9711219913) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4855609976 + 4855609977.

It is an arithmetic number, because the mean of its divisors is an integer number (4855609977).

Almost surely, 29711219953 is an apocalyptic number.

It is an amenable number.

9711219953 is a deficient number, since it is larger than the sum of its proper divisors (1).

9711219953 is an equidigital number, since it uses as much as digits as its factorization.

9711219953 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 153090, while the sum is 47.

The square root of 9711219953 is about 98545.5222371874. The cubic root of 9711219953 is about 2133.4932028928.

The spelling of 9711219953 in words is "nine billion, seven hundred eleven million, two hundred nineteen thousand, nine hundred fifty-three".