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97114333328461 is a prime number
BaseRepresentation
bin10110000101001100110001…
…010101110011010001001101
3110201212001001212101010100101
4112011030301111303101031
5100212110123313002321
6542313413035131101
726312164466142241
oct2605146125632115
9421761055333311
1097114333328461
1128a41a594423a9
12aa854a98a3a91
134225ac4801427
1419da504820421
15b362777dc791
hex58533157344d

97114333328461 has 2 divisors, whose sum is σ = 97114333328462. Its totient is φ = 97114333328460.

The previous prime is 97114333328447. The next prime is 97114333328483. The reversal of 97114333328461 is 16482333341179.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 57893548305961 + 39220785022500 = 7608781^2 + 6262650^2 .

It is a cyclic number.

It is not a de Polignac number, because 97114333328461 - 213 = 97114333320269 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (97114333328561) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48557166664230 + 48557166664231.

It is an arithmetic number, because the mean of its divisors is an integer number (48557166664231).

Almost surely, 297114333328461 is an apocalyptic number.

It is an amenable number.

97114333328461 is a deficient number, since it is larger than the sum of its proper divisors (1).

97114333328461 is an equidigital number, since it uses as much as digits as its factorization.

97114333328461 is an evil number, because the sum of its binary digits is even.

The product of its digits is 7838208, while the sum is 55.

The spelling of 97114333328461 in words is "ninety-seven trillion, one hundred fourteen billion, three hundred thirty-three million, three hundred twenty-eight thousand, four hundred sixty-one".