Base | Representation |
---|---|
bin | 1000110110100110000001… |
… | …0010100110111101011011 |
3 | 1021110120011222201112022221 |
4 | 2031221200102212331123 |
5 | 2233440223403234033 |
6 | 32411424301524511 |
7 | 2023154606405551 |
oct | 215514022467533 |
9 | 37416158645287 |
10 | 9734011383643 |
11 | 311319772a748 |
12 | 1112624873737 |
13 | 557bb479a9c1 |
14 | 2591b30adbd1 |
15 | 11d30d63112d |
hex | 8da604a6f5b |
9734011383643 has 2 divisors, whose sum is σ = 9734011383644. Its totient is φ = 9734011383642.
The previous prime is 9734011383641. The next prime is 9734011383661. The reversal of 9734011383643 is 3463831104379.
9734011383643 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 9734011383643 - 21 = 9734011383641 is a prime.
It is a super-2 number, since 2×97340113836432 (a number of 27 digits) contains 22 as substring.
Together with 9734011383641, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (9734011383641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4867005691821 + 4867005691822.
It is an arithmetic number, because the mean of its divisors is an integer number (4867005691822).
Almost surely, 29734011383643 is an apocalyptic number.
9734011383643 is a deficient number, since it is larger than the sum of its proper divisors (1).
9734011383643 is an equidigital number, since it uses as much as digits as its factorization.
9734011383643 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3919104, while the sum is 52.
The spelling of 9734011383643 in words is "nine trillion, seven hundred thirty-four billion, eleven million, three hundred eighty-three thousand, six hundred forty-three".
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