Search a number
-
+
973483331 is a prime number
BaseRepresentation
bin111010000001100…
…010110101000011
32111211210002002012
4322001202311003
53443202431311
6240333043135
733060320552
oct7201426503
92454702065
10973483331
1145a562487
122320264ab
131268b4852
1493407d99
155a6e478b
hex3a062d43

973483331 has 2 divisors, whose sum is σ = 973483332. Its totient is φ = 973483330.

The previous prime is 973483309. The next prime is 973483333. The reversal of 973483331 is 133384379.

It is a strong prime.

It is an emirp because it is prime and its reverse (133384379) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 973483331 - 218 = 973221187 is a prime.

It is a super-2 number, since 2×9734833312 = 1895339591469711122, which contains 22 as substring.

Together with 973483333, it forms a pair of twin primes.

It is a Chen prime.

It is equal to p49567019 and since 973483331 and 49567019 have the same sum of digits, it is a Honaker prime.

It is not a weakly prime, because it can be changed into another prime (973483333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 486741665 + 486741666.

It is an arithmetic number, because the mean of its divisors is an integer number (486741666).

Almost surely, 2973483331 is an apocalyptic number.

973483331 is a deficient number, since it is larger than the sum of its proper divisors (1).

973483331 is an equidigital number, since it uses as much as digits as its factorization.

973483331 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 163296, while the sum is 41.

The square root of 973483331 is about 31200.6943993239. The cubic root of 973483331 is about 991.0818127019.

The spelling of 973483331 in words is "nine hundred seventy-three million, four hundred eighty-three thousand, three hundred thirty-one".