Base | Representation |
---|---|
bin | 10110001110101100101101… |
… | …111011000101000000010001 |
3 | 110211011110000001202201200122 |
4 | 112032230231323011000101 |
5 | 100303304020410124221 |
6 | 543533331334400025 |
7 | 26410304103030563 |
oct | 2616545573050021 |
9 | 424143001681618 |
10 | 97767111020561 |
11 | 2917388742a154 |
12 | ab6bb07800015 |
13 | 4272525817b38 |
14 | 1a1dd4c28d333 |
15 | b48230cceeab |
hex | 58eb2dec5011 |
97767111020561 has 2 divisors, whose sum is σ = 97767111020562. Its totient is φ = 97767111020560.
The previous prime is 97767111020519. The next prime is 97767111020569. The reversal of 97767111020561 is 16502011176779.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 90222338119936 + 7544772900625 = 9498544^2 + 2746775^2 .
It is a cyclic number.
It is not a de Polignac number, because 97767111020561 - 230 = 97766037278737 is a prime.
It is not a weakly prime, because it can be changed into another prime (97767111020569) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 48883555510280 + 48883555510281.
It is an arithmetic number, because the mean of its divisors is an integer number (48883555510281).
Almost surely, 297767111020561 is an apocalyptic number.
It is an amenable number.
97767111020561 is a deficient number, since it is larger than the sum of its proper divisors (1).
97767111020561 is an equidigital number, since it uses as much as digits as its factorization.
97767111020561 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1111320, while the sum is 53.
The spelling of 97767111020561 in words is "ninety-seven trillion, seven hundred sixty-seven billion, one hundred eleven million, twenty thousand, five hundred sixty-one".
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