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98034442001 is a prime number
BaseRepresentation
bin101101101001101001…
…1101101111100010001
3100101001012002122120022
41123103103231330101
53101233304121001
6113011510153225
710040246002466
oct1332323557421
9311035078508
1098034442001
1138637983301
1216bbb652815
139324534182
144a5ddad66d
15283b8cc11b
hex16d34edf11

98034442001 has 2 divisors, whose sum is σ = 98034442002. Its totient is φ = 98034442000.

The previous prime is 98034441959. The next prime is 98034442003. The reversal of 98034442001 is 10024443089.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97909539025 + 124902976 = 312905^2 + 11176^2 .

It is an emirp because it is prime and its reverse (10024443089) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 98034442001 - 218 = 98034179857 is a prime.

It is a super-2 number, since 2×980344420012 (a number of 23 digits) contains 22 as substring.

Together with 98034442003, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (98034442003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49017221000 + 49017221001.

It is an arithmetic number, because the mean of its divisors is an integer number (49017221001).

Almost surely, 298034442001 is an apocalyptic number.

It is an amenable number.

98034442001 is a deficient number, since it is larger than the sum of its proper divisors (1).

98034442001 is an equidigital number, since it uses as much as digits as its factorization.

98034442001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27648, while the sum is 35.

The spelling of 98034442001 in words is "ninety-eight billion, thirty-four million, four hundred forty-two thousand, one".