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98052993373 is a prime number
BaseRepresentation
bin101101101010001101…
…0011111000101011101
3100101002111000011021011
41123110122133011131
53101303031241443
6113013411535221
710040562456226
oct1332432370535
9311074004234
1098052993373
11386473a4215
12170058ba511
13932832b10a
144a6263c24d
15283d343b9d
hex16d469f15d

98052993373 has 2 divisors, whose sum is σ = 98052993374. Its totient is φ = 98052993372.

The previous prime is 98052993331. The next prime is 98052993413. The reversal of 98052993373 is 37339925089.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 57072254404 + 40980738969 = 238898^2 + 202437^2 .

It is an emirp because it is prime and its reverse (37339925089) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-98052993373 is a prime.

It is a super-2 number, since 2×980529933732 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (98052933373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49026496686 + 49026496687.

It is an arithmetic number, because the mean of its divisors is an integer number (49026496687).

Almost surely, 298052993373 is an apocalyptic number.

It is an amenable number.

98052993373 is a deficient number, since it is larger than the sum of its proper divisors (1).

98052993373 is an equidigital number, since it uses as much as digits as its factorization.

98052993373 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11022480, while the sum is 58.

The spelling of 98052993373 in words is "ninety-eight billion, fifty-two million, nine hundred ninety-three thousand, three hundred seventy-three".