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98093546141 is a prime number
BaseRepresentation
bin101101101011011010…
…1001011101010011101
3100101012022022110012112
41123112311023222131
53101343421434031
6113021421043405
710041564245663
oct1332665135235
9311168273175
1098093546141
11386682820a8
12170173b6565
139333859436
144a67b96c33
152841ba462b
hex16d6d4ba9d

98093546141 has 2 divisors, whose sum is σ = 98093546142. Its totient is φ = 98093546140.

The previous prime is 98093546107. The next prime is 98093546167. The reversal of 98093546141 is 14164539089.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 95947540516 + 2146005625 = 309754^2 + 46325^2 .

It is an emirp because it is prime and its reverse (14164539089) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 98093546141 - 222 = 98089351837 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 98093546141.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (98093546641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49046773070 + 49046773071.

It is an arithmetic number, because the mean of its divisors is an integer number (49046773071).

Almost surely, 298093546141 is an apocalyptic number.

It is an amenable number.

98093546141 is a deficient number, since it is larger than the sum of its proper divisors (1).

98093546141 is an equidigital number, since it uses as much as digits as its factorization.

98093546141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 933120, while the sum is 50.

The spelling of 98093546141 in words is "ninety-eight billion, ninety-three million, five hundred forty-six thousand, one hundred forty-one".