981126889 has 2 divisors, whose sum is σ = 981126890. Its totient is φ = 981126888.

The previous prime is 981126877. The next prime is 981126901. The reversal of 981126889 is 988621189.

It is a balanced prime because it is at equal distance from previous prime (981126877) and next prime (981126901).

It can be written as a sum of positive squares in only one way, i.e., 906010000 + 75116889 = 30100^2 + 8667^2 .

It is an emirp because it is prime and its reverse (988621189) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 981126889 - 2⁵ = 981126857 is a prime.

It is a super-3 number, since 3×981126889³ (a number of 28 digits) contains 333 as substring.

It is equal to p_49935994 and since 981126889 and 49935994 have the same sum of digits, it is a Honaker prime.

It is not a weakly prime, because it can be changed into another prime (981126589) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 490563444 + 490563445.

It is an arithmetic number, because the mean of its divisors is an integer number (490563445).

Almost surely, 2^981126889 is an apocalyptic number.

It is an amenable number.

981126889 is a deficient number, since it is larger than the sum of its proper divisors (1).

981126889 is an equidigital number, since it uses as much as digits as its factorization.

981126889 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 497664, while the sum is 52.

The square root of 981126889 is about 31322.9450882257. The cubic root of 981126889 is about 993.6689655901.

Subtracting from 981126889 its product of digits (497664), we obtain a square (980629225 = 31315²).

The spelling of 981126889 in words is "nine hundred eighty-one million, one hundred twenty-six thousand, eight hundred eighty-nine".