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98115618645557 is a prime number
BaseRepresentation
bin10110010011110001010010…
…100110001010011000110101
3110212101202120011100102102022
4112103301102212022120311
5100330011241333124212
6544401405402322525
726444422331666402
oct2623612246123065
9425352504312368
1098115618645557
1129298666947027
12b00756a1b9445
134299356163a16
141a32b6d8452a9
15b5232bce3772
hex593c5298a635

98115618645557 has 2 divisors, whose sum is σ = 98115618645558. Its totient is φ = 98115618645556.

The previous prime is 98115618645511. The next prime is 98115618645587. The reversal of 98115618645557 is 75554681651189.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 70167997169956 + 27947621475601 = 8376634^2 + 5286551^2 .

It is a cyclic number.

It is not a de Polignac number, because 98115618645557 - 212 = 98115618641461 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (98115618645587) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49057809322778 + 49057809322779.

It is an arithmetic number, because the mean of its divisors is an integer number (49057809322779).

Almost surely, 298115618645557 is an apocalyptic number.

It is an amenable number.

98115618645557 is a deficient number, since it is larger than the sum of its proper divisors (1).

98115618645557 is an equidigital number, since it uses as much as digits as its factorization.

98115618645557 is an evil number, because the sum of its binary digits is even.

The product of its digits is 362880000, while the sum is 71.

The spelling of 98115618645557 in words is "ninety-eight trillion, one hundred fifteen billion, six hundred eighteen million, six hundred forty-five thousand, five hundred fifty-seven".