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98136740057 is a prime number
BaseRepresentation
bin101101101100101100…
…1111101000011011001
3100101022022120221010012
41123121121331003121
53101441001140212
6113030002531305
710042630345526
oct1333131750331
9311268527105
1098136740057
113868a6a4354
1217029966b35
13933c7a0975
144a6d7dc14d
152845887922
hex16d967d0d9

98136740057 has 2 divisors, whose sum is σ = 98136740058. Its totient is φ = 98136740056.

The previous prime is 98136740041. The next prime is 98136740059. The reversal of 98136740057 is 75004763189.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 90439134361 + 7697605696 = 300731^2 + 87736^2 .

It is an emirp because it is prime and its reverse (75004763189) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 98136740057 - 24 = 98136740041 is a prime.

Together with 98136740059, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 98136739987 and 98136740014.

It is not a weakly prime, because it can be changed into another prime (98136740059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49068370028 + 49068370029.

It is an arithmetic number, because the mean of its divisors is an integer number (49068370029).

Almost surely, 298136740057 is an apocalyptic number.

It is an amenable number.

98136740057 is a deficient number, since it is larger than the sum of its proper divisors (1).

98136740057 is an equidigital number, since it uses as much as digits as its factorization.

98136740057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1270080, while the sum is 50.

The spelling of 98136740057 in words is "ninety-eight billion, one hundred thirty-six million, seven hundred forty thousand, fifty-seven".