Search a number
-
+
981786150481 is a prime number
BaseRepresentation
bin11100100100101110000…
…00111100011001010001
310110212011100212000001211
432102113000330121101
5112041144223303411
62031005404300121
7130634401404643
oct16222700743121
93425140760054
10981786150481
113494117611a4
1213a33a241641
13717749721a6
1435739470893
151a81271a221
hexe49703c651

981786150481 has 2 divisors, whose sum is σ = 981786150482. Its totient is φ = 981786150480.

The previous prime is 981786150421. The next prime is 981786150539. The reversal of 981786150481 is 184051687189.

It is an a-pointer prime, because the next prime (981786150539) can be obtained adding 981786150481 to its sum of digits (58).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 808846610881 + 172939539600 = 899359^2 + 415860^2 .

It is an emirp because it is prime and its reverse (184051687189) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 981786150481 - 27 = 981786150353 is a prime.

It is a super-2 number, since 2×9817861504812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (981786150421) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 490893075240 + 490893075241.

It is an arithmetic number, because the mean of its divisors is an integer number (490893075241).

Almost surely, 2981786150481 is an apocalyptic number.

It is an amenable number.

981786150481 is a deficient number, since it is larger than the sum of its proper divisors (1).

981786150481 is an equidigital number, since it uses as much as digits as its factorization.

981786150481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3870720, while the sum is 58.

The spelling of 981786150481 in words is "nine hundred eighty-one billion, seven hundred eighty-six million, one hundred fifty thousand, four hundred eighty-one".