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9820043 is a prime number
BaseRepresentation
bin100101011101…
…011110001011
3200110220120022
4211131132023
510003220133
6550251055
7146316602
oct45353613
920426508
109820043
1155a7a42
123356a8b
13205a99c
141438a39
15cde998
hex95d78b

9820043 has 2 divisors, whose sum is σ = 9820044. Its totient is φ = 9820042.

The previous prime is 9820037. The next prime is 9820049. The reversal of 9820043 is 3400289.

It is a balanced prime because it is at equal distance from previous prime (9820037) and next prime (9820049).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-9820043 is a prime.

It is a Sophie Germain prime.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 9819994 and 9820021.

It is not a weakly prime, because it can be changed into another prime (9820049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4910021 + 4910022.

It is an arithmetic number, because the mean of its divisors is an integer number (4910022).

Almost surely, 29820043 is an apocalyptic number.

9820043 is a deficient number, since it is larger than the sum of its proper divisors (1).

9820043 is an equidigital number, since it uses as much as digits as its factorization.

9820043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 26.

The square root of 9820043 is about 3133.6947841167. The cubic root of 9820043 is about 214.1432862854.

The spelling of 9820043 in words is "nine million, eight hundred twenty thousand, forty-three".