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98502470315141 is a prime number
BaseRepresentation
bin10110011001011001100100…
…110000001010110010000101
3110220202202002112000101212112
4112121121210300022302011
5100402331024400041031
6545255224332230405
726514366016635524
oct2631314460126205
9426682075011775
1098502470315141
11294277325a2152
12b06a53200b405
1342c6987767399
141a4778b6aa4bb
15b5c41e23a62b
hex599664c0ac85

98502470315141 has 2 divisors, whose sum is σ = 98502470315142. Its totient is φ = 98502470315140.

The previous prime is 98502470315131. The next prime is 98502470315149. The reversal of 98502470315141 is 14151307420589.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80001039148900 + 18501431166241 = 8944330^2 + 4301329^2 .

It is a cyclic number.

It is not a de Polignac number, because 98502470315141 - 26 = 98502470315077 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 98502470315141.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (98502470315149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49251235157570 + 49251235157571.

It is an arithmetic number, because the mean of its divisors is an integer number (49251235157571).

Almost surely, 298502470315141 is an apocalyptic number.

It is an amenable number.

98502470315141 is a deficient number, since it is larger than the sum of its proper divisors (1).

98502470315141 is an equidigital number, since it uses as much as digits as its factorization.

98502470315141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1209600, while the sum is 50.

The spelling of 98502470315141 in words is "ninety-eight trillion, five hundred two billion, four hundred seventy million, three hundred fifteen thousand, one hundred forty-one".